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15c-c^2=20
We move all terms to the left:
15c-c^2-(20)=0
We add all the numbers together, and all the variables
-1c^2+15c-20=0
a = -1; b = 15; c = -20;
Δ = b2-4ac
Δ = 152-4·(-1)·(-20)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{145}}{2*-1}=\frac{-15-\sqrt{145}}{-2} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{145}}{2*-1}=\frac{-15+\sqrt{145}}{-2} $
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